Why does cos(90 - x) = sin(x) and sin(90 - x) = cos(x)?
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Note that the image below is only for x in Q1 (the first quadrant). If you wish you should be able to draw it with x in any quadrant. Definition of sin(x) (side opposite angle x)//(hypotenuse) Definition of cos(90^@ -x) (side adjacent to angle (90^@-x))//(hypotenuse) but (side opposite angle x) = (side adjacent to angle (90^@-x) Therefore sin(x) = cos(90^@ -x) Similarly cos(x) = sin(90^@ - x)
Give the coordinates of each image. $$ D _ { rac { 1 } {
Solved SSC CHSL 2 July 2019 Shift-2 Paper With Solutions PDF, PDF, Interest
Fill in the blank with the appropriate direction (left, righ
Trace triangle JKL and point P. Draw the dilation of triangl
Trace triangle JKL and point P. Draw the dilation of triangl
Fill in the blank with the appropriate direction (left, righ
Solved SSC CHSL 2 July 2019 Shift-2 Paper With Solutions PDF, PDF, Interest
Give the coordinates of each image. $$ D _ { rac { 1 } {
Trace triangle JKL and point P. Draw the dilation of triangl
Why does cos(90 - x) = sin(x) and sin(90 - x) = cos(x)?